Reasoning Practice: Alphabaticalseries Secondhalfreverse Mock Test – Free Online Practice

Reasoning Practice: Alphabaticalseries Secondhalfreverse ke liye free mock test: 7 questions, timer, negative marking aur explanation ke saath. Koi login nahi, koi payment nahi — turant shuru karein.

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Reasoning Practice: Alphabaticalseries Secondhalfreverse ke liye ye 7 questions ka practice set General Knowledge pattern par banaya gaya hai. Test me 45 second per question ka timer hai aur har galat answer par 0.25 marks kate jaate hain — bilkul asli exam jaisa. Submit karne ke baad aapko exact score, accuracy aur har question ka explanation milta hai. Bihar ke competitive exams (BPSC, BSSC, Bihar Police, BTSC) ki tayari karne wale students ke liye.

Practice Questions (7 of 7)

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1. If the second half is written in the reverse order then which letter will be 10th to the left of 14th from the left end?
   यदि द्वितीय अर्द्धांश को उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 14वें अक्षर के बाएँ 10वाँ अक्षर कौन-सा होगा?
   (A) (A) C

   (B) (B) D

   (C) (C) E

   (D) (D) F
   ✅ Answer & Explanation

   Sahi jawab: B) (B) D

   Explanation: Method 1 (First Half Unchanged Shortcut Trick): Step 1: Series structure samjhein: - First half (A se M): Normal sequence $A, B, C, \dots, L, M$ (1 se 13 tak). - Second half (N se Z) reversed: $Z, Y, X, \dots, O, N$ (14 se 26 tak). Step 2: Samaan dishaon (Left aur Left) ke liye positions ko ghataayein: $$\text{Position from Left} = 14 - 10 = 4\text{th letter}$$ Step 3: Chuki $4 \le 13$, yeh letter unchanged first half me aata hai. - 'A' se shuru hone wali normal series me 4th letter 'D' hota hai. Correct option (B) D hai. Method 2 (Direct Alphabet Inspection): First half bilkul normal order me hai, isliye baayein se chautha letter seedhe 'D' hoga. Sahi uttar (B) hai.
2. If the second half is written in the reverse order then which letter will be 6th to the left of 15th from the left end?
   यदि द्वितीय अर्द्धांश को उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 15वें अक्षर के बाएँ छठा अक्षर कौन-सा होगा?
   (A) (A) H

   (B) (B) I

   (C) (C) J

   (D) (D) K
   ✅ Answer & Explanation

   Sahi jawab: B) (B) I

   Explanation: Method 1 (Within First-Half Boundary Shortcut): Step 1: Left se net position calculate karein: $$\text{Position from Left} = 15 - 6 = 9\text{th letter}$$ Step 2: $9 \le 13$ hone ke karan yeh letter normal first half ($A \dots M$) me hi sthit hai. Step 3: Normal alphabet me baayein se 9वाँ letter 'I' hota hai. Correct option (B) I hai. Method 2 (Visual Offset Method): 15th letter second half me tha, lekin 6 sthan piche aane par sthiti 9th ban jaati hai jo first half ka hissa hai. 'A' se 9th letter 'I' prapt hota hai. Sahi uttar (B) hai.
3. If the second half is written in the reverse order then which letter will be 5th to the right of 10th from the left end?
   यदि द्वितीय अर्द्धांश को उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 10वें अक्षर के दाएँ 5वाँ अक्षर कौन-सा होगा?
   (A) (A) X

   (B) (B) Y

   (C) (C) Z

   (D) (D) W
   ✅ Answer & Explanation

   Sahi jawab: B) (B) Y

   Explanation: Method 1 (Reversed Second-Half Offset Trick): Step 1: Baayein chhor se kul sthiti nikalein (Left + Right): $$\text{Position from Left} = 10 + 5 = 15\text{th letter}$$ Step 2: Pehle 13 letters first half ke paar karne par second half ($Z \dots N$) me sthiti: $$15 - 13 = 2\text{nd letter from 'Z'}$$ Step 3: 'Z' se countdown karein ($Z$ = 1st, $Y$ = 2nd) ya formula $(26 + 1 - 2 = 25)$ lagayein: $$\text{Original Position} = 25$$ 25वाँ letter 'Y' hota hai. Correct option (B) Y hai. Method 2 (Direct Inspection in Second Half): Second half baayein se shuru hota hai: $Z(14\text{th}), Y(15\text{th})$. 15th position par letter 'Y' aata hai. Sahi uttar (B) hai.
4. If the second half is written in the reverse order then which letter will be 7th to the right of 13th from the left end?
   यदि द्वितीय अर्द्धांश को उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 13वें अक्षर के दाएँ 7वाँ अक्षर कौन-सा होगा?
   (A) (A) S

   (B) (B) T

   (C) (C) U

   (D) (D) V
   ✅ Answer & Explanation

   Sahi jawab: B) (B) T

   Explanation: Method 1 (Second-Half Inversion Shortcut): Step 1: Left end se effective position nikalein: $$\text{Position from Left} = 13 + 7 = 20\text{th letter}$$ Step 2: First half (13 letters) hatane par second half me sthiti: $$20 - 13 = 7\text{th letter from 'Z'}$$ Step 3: 'Z' ki taraf se 7th letter ki original place value: $$\text{Original Position} = (26 + 1) - 7 = 20$$ Alphabet me 20वाँ letter 'T' hota hai. Correct option (B) T hai. Method 2 (Direct Countdown from Z): Second half sequence: $Z(1), Y(2), X(3), W(4), V(5), U(6), T(7)$. 7th letter 'T' prapt hota hai. Sahi uttar (B) hai.
5. If the second half is written in the reverse order then which letter will be 5th to the right of 10th from the right end?
   यदि द्वितीय अर्द्धांश को उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 10वें अक्षर के दाएँ 5वाँ अक्षर कौन-सा होगा?
   (A) (A) Q

   (B) (B) R

   (C) (C) S

   (D) (D) P
   ✅ Answer & Explanation

   Sahi jawab: B) (B) R

   Explanation: Method 1 (Right-to-Left in Second Half Shortcut): Step 1: Same directions (Right aur Right) hone par ghataayein: $$\text{Position from Right} = 10 - 5 = 5\text{th letter}$$ Step 2: Chuki $5 \le 13$, yeh letter reversed second half ($Z \dots N$) me daayein chhor par sthit hai. Step 3: Daayein (Right) end par letter 'N' (original 14th letter) hai, isliye 'N' se 5 kadam aage badhein: $$\text{Original Position} = 13 + 5 = 18$$ 18वाँ letter 'R' hota hai. Correct option (B) R hai. Method 2 (Sequential Counting from N): Daayein छोर se sequence: $N(1), O(2), P(3), Q(4), R(5)$. 5th letter 'R' hai. Sahi uttar (B) hai.
6. If the second half is written in the reverse order then which letter will be 5th to the right of 15th from the right end?
   यदि द्वितीय अर्द्धांश को उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 15वें अक्षर के दाएँ 5वाँ अक्षर कौन-सा होगा?
   (A) (A) V

   (B) (B) W

   (C) (C) X

   (D) (D) U
   ✅ Answer & Explanation

   Sahi jawab: B) (B) W

   Explanation: Method 1 (Second Half Offset from N Shortcut): Step 1: Right end se net position nikalein: $$\text{Position from Right} = 15 - 5 = 10\text{th letter}$$ Step 2: $10 \le 13$ hone ke karan yeh letter second half me hi hai. Step 3: Daayein chhor par 'N' (14th) hone se 'N' se 10वाँ letter: $$\text{Original Position} = 13 + 10 = 23$$ 23वाँ letter 'W' hota hai. Correct option (B) W hai. Method 2 (Counting from N Method): $N(1), O(2), P(3), Q(4), R(5), S(6), T(7), U(8), V(9), W(10)$. Daayein se 10th letter 'W' prapt hota hai. Sahi uttar (B) hai.
7. If the second half is written in the reverse order then which letter will be 5th to the left of 11th from the right end?
   यदि द्वितीय अर्द्धांश को उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 11वें अक्षर के बाएँ 5वाँ अक्षर कौन-सा होगा?
   (A) (A) J

   (B) (B) K

   (C) (C) L

   (D) (D) I
   ✅ Answer & Explanation

   Sahi jawab: B) (B) K

   Explanation: Method 1 (Right-End Crossing into First Half Shortcut): Step 1: Right end se total position nikalein (Right + Left): $$\text{Position from Right} = 11 + 5 = 16\text{th letter}$$ Step 2: Total 26 letters me right se 16th letter ki left se sthiti nikalein: $$\text{Position from Left} = (26 + 1) - 16 = 11\text{th letter}$$ Step 3: Chuki $11 \le 13$, yeh letter normal first half ($A \dots M$) me sthit hai. - Normal alphabet me 11वाँ letter 'K' hota hai. Correct option (B) K hai. Method 2 (Boundary Subtraction Method): Second half ke 13 letters cross karne ke baad: $16 - 13 = 3$rd letter into first half from 'M'. 'M' se piche ki or: $M(1), L(2), K(3)$. Sahi uttar (B) hai.

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