Reasoning Practice: Alphabaticalseries Bothhalfreverseorder Mock Test – Free Online Practice

Reasoning Practice: Alphabaticalseries Bothhalfreverseorder ke liye free mock test: 8 questions, timer, negative marking aur explanation ke saath. Koi login nahi, koi payment nahi — turant shuru karein.

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Reasoning Practice: Alphabaticalseries Bothhalfreverseorder ke liye ye 8 questions ka practice set General Knowledge pattern par banaya gaya hai. Test me 45 second per question ka timer hai aur har galat answer par 0.25 marks kate jaate hain — bilkul asli exam jaisa. Submit karne ke baad aapko exact score, accuracy aur har question ka explanation milta hai. Bihar ke competitive exams (BPSC, BSSC, Bihar Police, BTSC) ki tayari karne wale students ke liye.

Practice Questions (8 of 8)

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1. If first half and second half both are written in the reverse order respectively then which letter will be 10th to the left of 9th from the right end?
   यदि प्रथम अर्द्धांश और द्वितीय अर्द्धांश दोनों को क्रमशः उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 9वें अक्षर के बाएँ 10वाँ अक्षर कौन-सा होगा?
   (A) (A) E

   (B) (B) F

   (C) (C) G

   (D) (D) H
   ✅ Answer & Explanation

   Sahi jawab: B) (B) F

   Explanation: Method 1 (Two Halves Reverse Shortcut Trick): Step 1: Series structure samjhein: - First half (A se M) reversed: $M, L, K, \dots, B, A$ (1 se 13 tak). - Second half (N se Z) reversed: $Z, Y, X, \dots, O, N$ (14 se 26 tak). Step 2: Effective position from Right end nikalte hain (Right + Left): $$\text{Position from Right} = 9 + 10 = 19\text{th letter}$$ Step 3: Daayein (Right) se aane par pehle 13 letters second half ($N \to Z$) ke aayenge. Bachenge: $$19 - 13 = 6\text{th letter from first half (A ki taraf se)}$$ - First half me 'A' boundary par hai ($A, B, C, D, E, F$), isliye 'A' se 6th letter 'F' hoga. Correct option (B) F hai. Method 2 (Left-End Conversion Method): - Total letters = 26. Position from Left end $= (26 + 1) - 19 = 8$th from Left. - First half me Left se shuruat 'M' (13) se hoti hai, isliye baayein se 8th letter: $14 - 8 = 6$th letter of alphabet = 'F'. Sahi uttar (B) hai.
2. If first half and second half both are written in the reverse order respectively then which letter will be 8th to the left of 15th from the right end?
   यदि प्रथम अर्द्धांश और द्वितीय अर्द्धांश दोनों को क्रमशः उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 15वें अक्षर के बाएँ 8वाँ अक्षर कौन-सा होगा?
   (A) (A) I

   (B) (B) K

   (C) (C) J

   (D) (D) H
   ✅ Answer & Explanation

   Sahi jawab: C) (C) J

   Explanation: Method 1 (Boundary Crossing Shortcut Trick): Step 1: Position from Right end nikalte hain (Right + Left): $$\text{Position from Right} = 15 + 8 = 23\text{rd letter}$$ Step 2: Second half ke 13 letters cross karne ke baad: $$23 - 13 = 10\text{th letter into first half from 'A'}$$ Step 3: First half me 'A' se shuru karte hue 10वाँ letter 'J' hota hai. Correct option (C) J hai. Method 2 (Left-End Offset Method): - Left se position $= (26 + 1) - 23 = 4$th from Left. - Baayein se 4th letter 'M' se counting me: $M(1), L(2), K(3), J(4)$. Sahi uttar (C) hai.
3. If first half and second half both are written in the reverse order respectively then which letter will be 6th to the right of 15th from the right end?
   यदि प्रथम अर्द्धांश और द्वितीय अर्द्धांश दोनों को क्रमशः उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 15वें अक्षर के दाएँ छठा अक्षर कौन-सा होगा?
   (A) (A) U

   (B) (B) V

   (C) (C) W

   (D) (D) T
   ✅ Answer & Explanation

   Sahi jawab: B) (B) V

   Explanation: Method 1 (Second-Half Direct Offset Trick): Step 1: Samaan disha (Right aur Right) hone par ghataate hain: $$\text{Position from Right} = 15 - 6 = 9\text{th letter}$$ Step 2: Chuki $9 \le 13$, yeh letter second half ($Z \to N$) me hi sthit hai. Step 3: Second half me daayein (Right) end par 'N' (14th) hai, isliye 'N' se 9 kadam aage: $$\text{Original Position} = 13 + 9 = 22$$ Alphabet me 22वाँ letter 'V' hota hai. Correct option (B) V hai. Method 2 (Sequential Forward Counting from N): Second half daayein se: $N(1), O(2), P(3), Q(4), R(5), S(6), T(7), U(8), V(9)$. 9th letter 'V' prapt hota hai. Sahi uttar (B) hai.
4. If first half and second half both are written in the reverse order respectively then which letter will be 11th to the right of 14th from the right end?
   यदि प्रथम अर्द्धांश और द्वितीय अर्द्धांश दोनों को क्रमशः उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 14वें अक्षर के दाएँ 11वाँ अक्षर कौन-सा होगा?
   (A) (A) P

   (B) (B) Q

   (C) (C) O

   (D) (D) R
   ✅ Answer & Explanation

   Sahi jawab: A) (A) P

   Explanation: Method 1 (Second-Half Subtraction Trick): Step 1: Same directions (Right aur Right) ke liye ghataav karein: $$\text{Position from Right} = 14 - 11 = 3\text{rd letter}$$ Step 2: $3 \le 13$ hone se yeh second half me hai jahan Right end par 'N' hai: $$\text{Original Position} = 13 + 3 = 16$$ 16वाँ letter 'P' hota hai. Correct option (A) P hai. Method 2 (Right-End Direct Counting Method): Second half daayein chhor se shuru hota hai: $N(1), O(2), P(3)$. 3rd position par aane wala letter 'P' hai. Sahi uttar (A) hai.
5. If first half and second half both are written in the reverse order respectively then which letter will be 8th to the right of 11th from the left end?
   यदि प्रथम अर्द्धांश और द्वितीय अर्द्धांश दोनों को क्रमशः उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 11वें अक्षर के दाएँ 8वाँ अक्षर कौन-सा होगा?
   (A) (A) T

   (B) (B) U

   (C) (C) V

   (D) (D) W
   ✅ Answer & Explanation

   Sahi jawab: B) (B) U

   Explanation: Method 1 (Left-to-Right Crossing into Second Half Trick): Step 1: Position from Left end nikalte hain (Left + Right): $$\text{Position from Left} = 11 + 8 = 19\text{th letter}$$ Step 2: Pehle 13 letters first half ($M \to A$) cross karne ke baad second half ($Z \to N$) me pravesh karein: $$19 - 13 = 6\text{th letter from 'Z'}$$ Step 3: 'Z' se 6th letter nikalne ke liye standard conversion rule $(27 - 6)$ lagayein: $$\text{Original Position} = 27 - 6 = 21$$ Alphabet me 21वाँ letter 'U' hota hai. Correct option (B) U hai. Method 2 (Direct Reverse Second Half Counting): Second half $Z$ se shuru hota hai: $Z(1), Y(2), X(3), W(4), V(5), U(6)$. 6th position par aane wala letter 'U' hai. Sahi uttar (B) hai.
6. If first half and second half both are written in the reverse order respectively then which letter will be 7th to the right of 16th from the left end?
   यदि प्रथम अर्द्धांश और द्वितीय अर्द्धांश दोनों को क्रमशः उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 16वें अक्षर के दाएँ 7वाँ अक्षर कौन-सा होगा?
   (A) (A) P

   (B) (B) Q

   (C) (C) R

   (D) (D) S
   ✅ Answer & Explanation

   Sahi jawab: B) (B) Q

   Explanation: Method 1 (Second-Half Left Offset Trick): Step 1: Position from Left end nikalein (Left + Right): $$\text{Position from Left} = 16 + 7 = 23\text{rd letter}$$ Step 2: Second half me 'Z' ki taraf se sthiti nikalein: $$23 - 13 = 10\text{th letter from 'Z'}$$ Step 3: 'Z' se 10th letter ka alphabetical code: $$\text{Original Position} = 27 - 10 = 17$$ 17वाँ letter 'Q' hota hai. Correct option (B) Q hai. Method 2 (Right-End Equivalent Method): - Right end se position $= (26 + 1) - 23 = 4$th from Right. - Second half daayein se 'N' se start hota hai: $N(1), O(2), P(3), Q(4)$. Sahi uttar (B) hai.
7. If first half and second half both are written in the reverse order respectively then which letter will be 5th to the left of 14th from the left end?
   यदि प्रथम अर्द्धांश और द्वितीय अर्द्धांश दोनों को क्रमशः उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 14वें अक्षर के बाएँ 5वाँ अक्षर कौन-सा होगा?
   (A) (A) D

   (B) (B) F

   (C) (C) E

   (D) (D) G
   ✅ Answer & Explanation

   Sahi jawab: C) (C) E

   Explanation: Method 1 (First-Half Within-Boundary Shortcut): Step 1: Samaan disha (Left aur Left) ke liye ghataayein: $$\text{Position from Left} = 14 - 5 = 9\text{th letter}$$ Step 2: Chuki $9 \le 13$, yeh first half ($M \to A$) me hi sthit hai. Step 3: First half me baayein se 'M' (13) se shuru hota hai. Iski actual value nikalne ke liye $(13 + 1) - 9$ karein: $$\text{Original Position} = 14 - 9 = 5$$ 5वाँ letter 'E' hota hai. Correct option (C) E hai. Method 2 (Direct Countdown from M): First half baayein se: $M(1), L(2), K(3), J(4), I(5), H(6), G(7), F(8), E(9)$. 9th letter 'E' prapt hota hai. Sahi uttar (C) hai.
8. If first half and second half both are written in the reverse order respectively then which letter will be 6th to the left of 10th from the left end?
   यदि प्रथम अर्द्धांश और द्वितीय अर्द्धांश दोनों को क्रमशः उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 10वें अक्षर के बाएँ छठा अक्षर कौन-सा होगा?
   (A) (A) I

   (B) (B) J

   (C) (C) K

   (D) (D) H
   ✅ Answer & Explanation

   Sahi jawab: B) (B) J

   Explanation: Method 1 (First-Half Left Subtraction Trick): Step 1: Same directions (Left aur Left) hone par ghataav karein: $$\text{Position from Left} = 10 - 6 = 4\text{th letter}$$ Step 2: Yeh first half ($M \to A$) me hi aata hai. 'M' se 4th letter ki normal position nikalein: $$\text{Original Position} = (13 + 1) - 4 = 14 - 4 = 10$$ Alphabet me 10वाँ letter 'J' hota hai. Correct option (B) J hai. Method 2 (Manual Inspection Method): First half: $M(1), L(2), K(3), J(4)$. Baayein chhor se chautha letter 'J' hai. Sahi uttar (B) hai.

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