Reasoning Practice: Alphabaticalseries Oddseries Mock Test – Free Online Practice

Reasoning Practice: Alphabaticalseries Oddseries ke liye free mock test: 4 questions, timer, negative marking aur explanation ke saath. Koi login nahi, koi payment nahi — turant shuru karein.

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Reasoning Practice: Alphabaticalseries Oddseries ke liye ye 4 questions ka practice set General Knowledge pattern par banaya gaya hai. Test me 45 second per question ka timer hai aur har galat answer par 0.25 marks kate jaate hain — bilkul asli exam jaisa. Submit karne ke baad aapko exact score, accuracy aur har question ka explanation milta hai. Bihar ke competitive exams (BPSC, BSSC, Bihar Police, BTSC) ki tayari karne wale students ke liye.

Practice Questions (4 of 4)

Neeche is set ke kuch questions hain — inhi par aapka timed test banega. Answer dekhne ke liye “Answer” par click karein.

1. If every alternative letter starting from B is deleted then which letter will be 5th to the right of 4th from the left end?
   यदि B से शुरू करते हुए प्रत्येक एकांतर (alternative) अक्षर को हटा दिया जाए, तो बाएँ छोर से चौथे अक्षर के दाएँ 5वाँ अक्षर कौन-सा होगा?
   (A) (A) P

   (B) (B) Q

   (C) (C) R

   (D) (D) S
   ✅ Answer & Explanation

   Sahi jawab: B) (B) Q

   Explanation: Method 1 (Odd Series $(2n - 1)$ Shortcut Trick): Step 1: B se shuru karke alternative letters (B, D, F, ...) hatane par visham sthanon (odd positions) wale letters bachenge: $$\text{Series}: \text{A, C, E, G, I, K, M, O, Q, S, U, W, Y (kul 13 letters)}$$ Step 2: Position from Left end calculate karein (Opposite directions = Addition): $$\text{Position from Left} = 4 + 5 = 9\text{th letter}$$ Step 3: Odd series me baayein se $n$-th letter ki real alphabetical position $(2n - 1)$ hoti hai: $$\text{Original Position} = (9 \times 2) - 1 = 18 - 1 = 17$$ Standard alphabet me 17वाँ letter 'Q' hota hai. Correct option (B) Q hai. Method 2 (Manual Counting Method): Odd series: A(1), C(2), E(3), G(4), I(5), K(6), M(7), O(8), Q(9). Baayein se 9th sthan par aane wala letter 'Q' hai. Sahi uttar (B) hai.
2. If every alternative letter starting from B is deleted then which letter will be 5th to the left of 12th from the left end?
   यदि B से शुरू करते हुए प्रत्येक एकांतर अक्षर को हटा दिया जाए, तो बाएँ छोर से 12वें अक्षर के बाएँ 5वाँ अक्षर कौन-सा होगा?
   (A) (A) M

   (B) (B) N

   (C) (C) K

   (D) (D) O
   ✅ Answer & Explanation

   Sahi jawab: A) (A) M

   Explanation: Method 1 (Odd Series $(2n - 1)$ Shortcut Trick): Step 1: Samaan dishaon (Left aur Left) ke liye ghataav (subtraction) karein: $$\text{Position from Left} = 12 - 5 = 7\text{th letter}$$ Step 2: Odd series me original position nikalne ka formula $(2n - 1)$ lagayein: $$\text{Original Position} = (7 \times 2) - 1 = 14 - 1 = 13$$ 13वाँ letter 'M' hota hai. Correct option (A) M hai. Method 2 (Direct Odd Sequence Counting): Odd series: A(1), C(2), E(3), G(4), I(5), K(6), M(7). 7th position par letter 'M' prapt hota hai. Sahi uttar (A) hai.
3. If every alternative letter starting from B is deleted then which letter will be 3rd to the left of 7th from the right end?
   यदि B से शुरू करते हुए प्रत्येक एकांतर अक्षर को हटा दिया जाए, तो दाएँ छोर से 7वें अक्षर के बाएँ तीसरा अक्षर कौन-सा होगा?
   (A) (A) E

   (B) (B) F

   (C) (C) G

   (D) (D) I
   ✅ Answer & Explanation

   Sahi jawab: C) (C) G

   Explanation: Method 1 (Odd Series Right-to-Left Conversion Shortcut): Step 1: Position from Right end nikalein (Right + Left): $$\text{Position from Right} = 7 + 3 = 10\text{th letter}$$ Step 2: Odd series me kul 13 letters hote hain, isliye Left end me convert karne ke liye $(13 + 1) = 14$ me se ghataayein: $$\text{Position from Left} = 14 - 10 = 4\text{th letter}$$ Step 3: Original alphabetical position ke liye $(2n - 1)$ apply karein: $$\text{Original Position} = (4 \times 2) - 1 = 8 - 1 = 7$$ 7वाँ letter 'G' hota hai. Correct option (C) G hai. Method 2 (Direct Backward Counting Method): Odd series daayein se: Y(1), W(2), U(3), S(4), Q(5), O(6), M(7), K(8), I(9), G(10). Daayein छोर se 10वाँ letter 'G' prapt hota hai. Sahi uttar (C) hai.
4. If every alternative letter starting from B is deleted then which letter will be 6th to the right of 12th from the right end?
   यदि B से शुरू करते हुए प्रत्येक एकांतर अक्षर को हटा दिया जाए, तो दाएँ छोर से 12वें अक्षर के दाएँ छठा अक्षर कौन-सा होगा?
   (A) (A) M

   (B) (B) N

   (C) (C) O

   (D) (D) Q
   ✅ Answer & Explanation

   Sahi jawab: C) (C) O

   Explanation: Method 1 (Odd Series Conversion Shortcut): Step 1: Samaan dishaon (Right aur Right) ke liye ghataayein: $$\text{Position from Right} = 12 - 6 = 6\text{th letter}$$ Step 2: Total 13 letters hone ke karan Left end me badlein: $$\text{Position from Left} = (13 + 1) - 6 = 14 - 6 = 8\text{th letter}$$ Step 3: Formula $(2n - 1)$ se original alphabet position nikalein: $$\text{Original Position} = (8 \times 2) - 1 = 16 - 1 = 15$$ 15वाँ letter 'O' hota hai. Correct option (C) O hai. Method 2 (Right End Inspection Method): Odd series piche se: Y(1), W(2), U(3), S(4), Q(5), O(6). Daayein chhor se 6th sthan par letter 'O' aata hai. Sahi uttar (C) hai.

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